Correct answer: \(\frac{1}{7}\)
Explanation:
In a non-leap year, there are 365 days. Dividing 365 by 7 gives: \[ 365 \div 7 = 52 \text{ weeks and } 1 \text{ extra day} \] Therefore, there will be exactly 52 occurrences of each day of the week, plus one additional day. The extra day could be any of the seven days of the week, so there is a \( \frac{1}{7} \) chance that the extra day will be a Thursday. If the extra day is a Thursday, there will be 53 Thursdays in that year. Hence, the probability that a non-leap year will have 53 Thursdays is \( \frac{1}{7} \).
Therefore, the probability is \(\frac{1}{7}\).