Question:

The probability of survival of a radioactive nucleus for one mean life is

Updated On: Jun 27, 2023
  • $\frac{1}{e}$
  • $1-\frac{1}{e}$
  • $\frac{1n 2}{e}$
  • $1-\frac{1n 2}{e}$
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The Correct Option is A

Approach Solution - 1

Probability of survival for any nucleus at time $t$ is $P = \frac{N}{N_0} = \frac{N_0 e^{- \lambda t}}{N_0} = e^{-\lambda t}$ So, in one mean life, required probability is $e^{- \lambda = \frac{1}{\lambda}} = \frac{1}{e}$
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Approach Solution -2

The probability of survival of a radioactive nucleus for one mean life is
a radioactive nucleus
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Concepts Used:

Nuclei

In the year 1911, Rutherford discovered the atomic nucleus along with his associates. It is already known that every atom is manufactured of positive charge and mass in the form of a nucleus that is concentrated at the center of the atom. More than 99.9% of the mass of an atom is located in the nucleus. Additionally, the size of the atom is of the order of 10-10 m and that of the nucleus is of the order of 10-15 m.

Read More: Nuclei

Following are the terms related to nucleus:

  1. Atomic Number
  2. Mass Number
  3. Nuclear Size
  4. Nuclear Density
  5. Atomic Mass Unit