Step 1: Define Essential Prime Implicant (EPI).
An Essential Prime Implicant (EPI) is a prime implicant that covers a 1 that no other prime implicant covers.
Step 2: Explanation of Prime Implicant.
A Prime Implicant (PI) whose each 1 is covered by a minimum of one Essential Prime Implicant (EPI) is termed an Essential Prime Implicant. It means that the coverage of 1's is critical and cannot be omitted by any other implicant.
Step 3: Analysis of options.
- (A) Essential prime implicant: This is correct because the definition of EPI matches this description.
- (B) Selective prime implicant: This is incorrect as this term does not refer to the PI covered by EPIs.
- (C) False prime implicant: This is incorrect as false implicants do not satisfy the required conditions.
- (D) Redundant prime implicant: This is incorrect as redundant implicants are not essential to the minimization process.
Step 4: Conclusion.
The correct answer is (A) Essential prime implicant, as it fits the definition provided in the question.
Consider the following Karnaugh Map (K-map). Minimal Function generated by this Karnaugh map is:
In C language, mat[i][j] is equivalent to: (where mat[i][j] is a two-dimensional array)
Suppose a minimum spanning tree is to be generated for a graph whose edge weights are given below. Identify the graph which represents a valid minimum spanning tree?
\[\begin{array}{|c|c|}\hline \text{Edges through Vertex points} & \text{Weight of the corresponding Edge} \\ \hline (1,2) & 11 \\ \hline (3,6) & 14 \\ \hline (4,6) & 21 \\ \hline (2,6) & 24 \\ \hline (1,4) & 31 \\ \hline (3,5) & 36 \\ \hline \end{array}\]
Choose the correct answer from the options given below:
Match LIST-I with LIST-II
Choose the correct answer from the options given below:
Consider the following set of processes, assumed to have arrived at time 0 in the order P1, P2, P3, P4, and P5, with the given length of the CPU burst (in milliseconds) and their priority:
\[\begin{array}{|c|c|c|}\hline \text{Process} & \text{Burst Time (ms)} & \text{Priority} \\ \hline \text{P1} & 10 & 3 \\ \hline \text{P2} & 1 & 1 \\ \hline \text{P3} & 4 & 4 \\ \hline \text{P4} & 1 & 2 \\ \hline \text{P5} & 5 & 5 \\ \hline \end{array}\]
Using priority scheduling (where priority 1 denotes the highest priority and priority 5 denotes the lowest priority), find the average waiting time.