Question

The pressure drop of water flowing through a pipe between two points is measured by using a vertical U-tube manometer. The manometer uses a liquid of density \( 2000 \) kg/m³. The difference in height of the liquid column in two limbs is \( 10 \) cm. The pressure drop between the two points is:

• A. \( 98.1 \) N/m²
• B. \( 981 \) N/m²
• C. \( 1962 \) N/m²
• D. \( 19620 \) N/m²

Hint:

Use the formula \( \Delta P = \rho g h \) for pressure drop calculations in manometers.

Answer 1

The Correct Option is C

Step 1: The pressure drop in a manometer is given by: \[ \Delta P = \rho g h \] where: - \( \rho = 2000 \) kg/m³ (density), - \( g = 9.81 \) m/s² (acceleration due to gravity), - \( h = 10 \) cm = \( 0.1 \) m. Step 2: Substituting the values: \[ \Delta P = 2000 \times 9.81 \times 0.1 \] \[ \Delta P = 1962 { N/m}^2 \] Thus, the correct answer is (C) 1962 N/m².