The power \( P \) of a lens is given by the formula:
\[
P = \frac{1}{f}
\]
where \( f \) is the focal length of the lens.
For a combination of lenses in contact, the total power is the sum of the individual powers:
\[
P_{\text{total}} = P_1 + P_2
\]
where \( P_1 \) is the power of the convex lens and \( P_2 \) is the power of the concave lens.
The power of the convex lens with focal length 40 cm is:
\[
P_1 = \frac{1}{40 \, \text{cm}} = \frac{1}{0.4 \, \text{m}} = +2.5 \, \text{D}
\]
The power of the concave lens with focal length 25 cm is:
\[
P_2 = \frac{1}{-0.25 \, \text{m}} = -4 \, \text{D}
\]
Thus, the total power is:
\[
P_{\text{total}} = 2.5 \, \text{D} + (-4 \, \text{D}) = -1.5 \, \text{D}
\]
Therefore, the correct answer is (a).