Step 1: Understand the problem.
The populations of two cities, X and Y, are initially equal. The population of city X increases by 15% in the first year and 20% in the second year. The population of city Y increases by 10% in the first year and 30% in the second year. After two years, the difference in population between the two cities is 55,980. We need to find the initial total population of both cities.
Step 2: Define variables.
Let the initial population of each city be \( P \). Therefore, the total initial population of both cities is \( 2P \).
Step 3: Calculate the population after two years for both cities.
For city X, the population increases as follows:
- After the first year: \( P \times 1.15 \) (15% increase)
- After the second year: \( P \times 1.15 \times 1.20 \)
The population of city X after two years is:
\[
\text{Population of X after 2 years} = P \times 1.15 \times 1.20 = P \times 1.38
\]
For city Y, the population increases as follows:
- After the first year: \( P \times 1.10 \) (10% increase)
- After the second year: \( P \times 1.10 \times 1.30 \)
The population of city Y after two years is:
\[
\text{Population of Y after 2 years} = P \times 1.10 \times 1.30 = P \times 1.43
\]
Step 4: Set up the equation for the difference in population.
The difference in population after two years is given as 55,980. Therefore:
\[
\text{Population of Y after 2 years} - \text{Population of X after 2 years} = 55,980
\]
Substituting the expressions for the populations:
\[
P \times 1.43 - P \times 1.38 = 55,980
\]
Simplifying:
\[
P \times (1.43 - 1.38) = 55,980
\]
\[
P \times 0.05 = 55,980
\]
Solving for \( P \):
\[
P = \frac{55,980}{0.05} = 1,11,960
\]
Step 5: Calculate the total initial population.
The total initial population of both cities is:
\[
\text{Total initial population} = 2P = 2 \times 1,11,960 = 2,23,920
\]
So, the total initial population of both cities is Rs. 2,23,920.
Step 6: Conclusion.
The total initial population of both cities is Rs. 6,22,000.
Final Answer:
The correct answer is (C): 6,22,000.