Step 1: Understand the effect of a half-wave plate.
A half-wave ($\lambda/2$) plate rotates the plane of polarisation by an amount equal to
$2\alpha$, where $\alpha$ is the angle between the incident polarisation and the fast axis.
Step 2: Use the given rotation.
Given rotation = $60^\circ$, therefore
$2\alpha = 60^\circ \;\Rightarrow\; \alpha = 30^\circ$.
Step 3: Exclude quarter-wave plates.
A quarter-wave ($\lambda/4$) plate changes linear polarisation to elliptical or circular,
not simply rotate it; hence $\lambda/4$ plates cannot produce pure rotation.
Step 4: Conclusion.
Thus, the correct wave plate is a $\lambda/2$ plate and $\alpha = 30^\circ$.
As shown in the figure, an electromagnetic wave with intensity $I_I$ is incident at the interface of two media having refractive indices $n_1 = 1$ and $n_2 = \sqrt{3}$. The wave is reflected with intensity $I_R$ and transmitted with intensity $I_T$. Permeability of each medium is the same. (Reflection coefficient $R = \frac{I_R}{I_I}$ and Transmission coefficient $T = \frac{I_T}{I_I}$). Choose the correct statement(s).
A beam of light traveling horizontally consists of an unpolarized component with intensity \( I_0 \) and a polarized component with intensity \( I_p \). The plane of polarization is oriented at an angle \( \theta \) with respect to the vertical. The figure shows the total intensity \( I_{\text{total}} \) after the light passes through a polarizer as a function of the angle \( \alpha \), that the axis of the polarizer makes with respect to the vertical. Identify the correct statement(s). 
