Question:
The plane containing the point (3, 2, 0) and the line \(\frac{x-3}{1}= \frac{y-6}{5}=\frac{z-4}{4}\) is
The plane containing the point (3, 2, 0) and the line \(\frac{x-3}{1}= \frac{y-6}{5}=\frac{z-4}{4}\) is
Updated On: Apr 26, 2024
- x-y+z=1
- x+y+z=5
- x+2y-z=1
- 2x-y+z=5
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The Correct Option is A
Solution and Explanation
The correct answer is Option (A) : x-y+z=1
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