2.5 x 10$^{-4}$
Step 1: Understand Darcy’s law
Darcy’s velocity (q) = Permeability ($k$) $\times$ Hydraulic gradient ($i$).
Given: $k = 2 \times 10^{-4}$ cm/s, $i = 0.5$.
Step 2: Calculate Darcy’s velocity
$q = k \times i = 2 \times 10^{-4} \times 0.5 = 1 \times 10^{-4}$ cm/s.
Step 3: Relate to seepage velocity
Seepage velocity ($v_s$) = $\frac{\text{Darcy’s velocity}}{\text{Porosity}}$.
Given porosity ($n$) = 0.4.
$v_s = \frac{1 \times 10^{-4}}{0.4} = 2.5 \times 10^{-4}$ cm/s.
A sediment core of 4 cm diameter and 35.81 cm height was collected. This core had an initial weight of 1000.00 g and upon drying the sediment, the weight decreased by 133.75 g. This core has a void ratio of 0.42857, where void ratio is defined as the ratio of volume of void to the volume of solid (Vv/Vs). The average density of the sediment in the core is ________ g/cm\(^3\).
A hillslope is shown below. If the area over the failure plane is 50 m\(^2\) and the weight of the hillslope material (W) is 2000 tons, the Factor of Safety (FOS) for this hillslope in dry conditions is ________.
Cohesion along failure plane = 196 kPa, Dip of failure plane = 60°, Internal friction angle = 30°, Area over failure plane = 50 m\(^2\), Weight of hillslope material = 2000 tons (Round off to two decimal places)