Question:

The period of \( 2 \sin 4x \cos 4x \) is:

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The period of a sine or cosine function is \( \frac{2\pi}{|A|} \) where \( A \) is the coefficient of \( x \).
Updated On: Mar 10, 2025
  • \( \frac{2\pi}{3} \)
  • \( \frac{2\pi}{4} \)
  • \( \frac{\pi}{2} \)
  • \( \frac{\pi}{4} \)
  • \( \pi \)
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The Correct Option is D

Solution and Explanation

The period of \( \sin A \cos A \) is given by \( \frac{2\pi}{|A|} \). 
Here, \( A = 4x \), so the period of \( 2 \sin 4x \cos 4x \) is: \[ \frac{2\pi}{4} = \frac{\pi}{4} \] Thus, the correct answer is \( \frac{\pi}{4} \).

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