Question

The percentage by volume of C3H8 in a mixture of C3H8, CH4 and CO is 36.5. Calculate the volume of CO2 produced when 100 ml of the mixture is burnt in excess of O2.

• (A) 175 ml
• (B) 173 ml
• (C) 150 ml
• (D) 123 ml

Answer 1

The Correct Option is B

Explanation:
Let the volumes of C3H8, CH4 and CO in the mixture be a, b and c m, respectively.Then, a + b + c = 100 ……. (i)Also, a = 36.5 …… (ii)Combustion reactions are as follow:C3H8 + 5O2 → 3CO2 + 4H2OCH4 + 2O2 → CO2 + 2H2OCO + ½O2 → CO2Therefore, volume of CO2 formed as a combustion of the mixture = 3a + b + c 3 X 36.5 + (b + c) = 3 X 36.5 + (100 - 36.5) = 173 ml