Question

The pair of compounds having the same hybridization for the central atom is:

• A. \( \text{Ni(CO)}_4 \) and \( [\text{PtCl}_4]^{2-} \)
• B. \( \text{Ni(CO)}_4 \) and \( \text{XeO}_2\text{F}_2 \)
• C. \( \text{XeF}_4 \) and \( [\text{SF}_4]^{2-} \)
• D. \( [\text{Co(NH}_3)_6]^{3+} \) and \( [\text{Co(H}_2\text{O})_6]^{3+} \)

Hint:

When determining hybridization, focus on the number of bonds and lone pairs around the central atom. The geometry and hybridization are determined by these factors.

Answer 1

The Correct Option is D

Step 1: Hybridization of the central atom.
- In \( \text{Ni(CO)}_4 \), the nickel atom undergoes sp\(^3\) hybridization. - In \( [\text{PtCl}_4]^{2-} \), the platinum atom also undergoes sp\(^3\) hybridization. - In \( \text{XeO}_2\text{F}_2 \), xenon undergoes sp\(^3\) hybridization. - In \( \text{XeF}_4 \), xenon undergoes sp\(^3\)d\(^2\) hybridization. - In \( [\text{SF}_4]^{2-} \), sulfur undergoes sp\(^3\)d hybridization. - In \( [\text{Co(NH}_3)_6]^{3+} \) and \( [\text{Co(H}_2\text{O})_6]^{3+} \), cobalt undergoes d\(^2\)sp\(^3\) hybridization in both cases.
Step 2: Conclusion.
The pair of compounds with the same hybridization for the central atom is (4) \( [\text{Co(NH}_3)_6]^{3+} \) and \( [\text{Co(H}_2\text{O})_6]^{3+} \) as both involve the central cobalt atom with d\(^2\)sp\(^3\) hybridization.