Question:

For the complex \( [Co(NH_3)_6]^{3+} \), what is the oxidation state of Co and the number of unpaired electrons?

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For coordination complexes, the oxidation state of the metal ion is determined by the charge on the complex and the nature of the ligands.
Updated On: Jan 20, 2026
  • \( x = 2, y = 2 \)
  • \( x = 3, y = 3 \)
  • \( x = 3, y = 4 \)
  • \( x = 4, y = 2 \)
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The Correct Option is B

Solution and Explanation


Step 1: Understanding the Complex.
The complex is \( [Co(NH_3)_6]^{3+} \), and ammonia (NH\(_3\)) is a neutral ligand. The charge on the complex is +3, meaning the charge on the central metal ion \( Co^{3+} \) is +3.
Step 2: Determining Oxidation State and Unpaired Electrons.
For \( Co^{3+} \), the oxidation state of Co is +3. In a \( d^6 \) configuration for \( Co^{3+} \), the number of unpaired electrons is 3.
Step 3: Conclusion.
The correct answer is (B) \( x = 3, y = 3 \).
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