The oxide which cannot act as a reducing agent is
Reducing agents are substances that have the capacity to donate electrons, leading to the reduction of another species in a chemical reaction.
The correct answer is Option C) \({CO_2}\)
When a substance loses electrons by increasing its oxidation state, it acts as a reducing agent.
In sulphur dioxide, sulphur has a +4 oxidation state. So, it increases its oxidation state to +6, therefore it acts as a reducing agent.
In Nitrogen Dioxide, nitrogen has a +4 oxidation state. So, it increases its oxidation state to +5, therefore it can also act as a reducing agent.
In carbon dioxide, carbon has the maximum oxidation state of + 4, therefore carbon dioxide \({(CO_2)}\) cannot act as a reducing agent.
In ClO2, chlorine is in a +4 oxidation state, it can increase its oxidation state to +7, therefore it can act as a reducing agent.
Therefore, Option C is the correct answer.
Discover More From Chapter: Redox Reactions
The correct answer is Option C) \({CO_2}\)
The real-life application of CO2 includes-
1) Used as a fire extinguisher.
2) CO2 is used in the beverages industry such as in soft drinks and also used to keep them cool.
The correct answer is Option C) \({CO_2}\)
Reducing agents are substances that have the capacity to donate electrons, leading to the reduction of another species in a chemical reaction. In the process, the reducing agent itself is oxidized, losing electrons.
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Sulphur dioxide, despite being an oxide, cannot act as a reducing agent due to the stability of its sulphur-oxygen bond. While reducing oxides typically donate electrons to facilitate the reduction of other species, sulphur dioxide does not possess this capability. Instead, it exhibits oxidizing properties under certain conditions.
The steam volatile compounds among the following are:
Choose the correct answer from the options given below:
Given below are two statements:
Statement (I): The first ionization energy of Pb is greater than that of Sn.
Statement (II): The first ionization energy of Ge is greater than that of Si.
In light of the above statements, choose the correct answer from the options given below:
\[ \begin{array}{|c|c|} \hline \textbf{LIST-I (Redox Reaction)} & \textbf{LIST-II (Type of Redox Reaction)} \\ \hline A. \, CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(l) & I. \, \text{Disproportionation reaction} \\ B. \, 2NaH(s) \rightarrow 2Na(s) + H_2(g) & II. \, \text{Combination reaction} \\ C. \, V_2O_5(s) + 5Ca(s) \rightarrow 2V(s) + 5CaO(s) & III. \, \text{Decomposition reaction} \\ D. \, 2H_2O(aq) \rightarrow 2H_2(g) + O_2(g) & IV. \, \text{Displacement reaction} \\ \hline \end{array} \]
Redox reactions are chemical reactions where oxidation and reduction take place simultaneously. In this type of reaction, there is a gain of electrons for one chemical species while the other loses electrons or simply involves transfer of electrons. The species that loses electrons is oxidized while the one that gains electrons is reduced.
Redox reactions can be differentiated into 4 categories namely combination reactions, decomposition reactions, displacement reactions, and disproportionation reactions. Each is explained separately below:
In this, the molecules combine to form new compounds. For example, when magnesium reacts to nitrogen.
Opposite to the combination reaction, here there is a breakdown of compounds to simpler substances. For example, electrolysis of water.
In this, the more reactive metal will displace the less reactive one in a chemical reaction. The reactivity of an element is represented in a series called the reactivity series (arranged in decreasing order of reactivity) which makes it easier to determine the chemical reaction and its products.
This is a peculiar type of reaction where an element showing a particular oxidation state will be oxidized and reduced simultaneously. Another thing to note is that these reactions will always have an element that can exhibit three oxidation states.