Question:

The oxidation state of sulphur in $Na_2S_4O_6$ is

Updated On: Jan 30, 2025
  • 6
  • $\frac{+3}{2}$
  • $\frac{+5}{2}$
  • -2
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The Correct Option is C

Solution and Explanation

The correct answer is C:\(\frac{+5}{2}\)
Let oxidation state of sulphur be \(x\)
Oxidation state of \(Na =+1\) 
Oxidation state of \(O =-2\) 
The average oxidation state of Sulphur 
\(\Rightarrow 2\left( Na ^{+}\right)+4( S )+6\left( O ^{2-}\right)=0\)
\(\Rightarrow 2(+1)+4( x )+6(-2)=0\)
\(\Rightarrow x =\frac{+5}{2}\)
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