Question

The oxidation state of sulphur in $Na_2S_4O_6$ is

• A. 6
• B. $\frac{+3}{2}$
• C. $\frac{+5}{2}$
• D. -2

Answer 1

The Correct Option is C

The correct answer is C:\(\frac{+5}{2}\)
Let oxidation state of sulphur be \(x\)
Oxidation state of \(Na =+1\) 
Oxidation state of \(O =-2\) 
The average oxidation state of Sulphur 
\(\Rightarrow 2\left( Na ^{+}\right)+4( S )+6\left( O ^{2-}\right)=0\)
\(\Rightarrow 2(+1)+4( x )+6(-2)=0\)
\(\Rightarrow x =\frac{+5}{2}\)