Step 1: Recall the oxidation number rules
In a molecule, the sum of the oxidation states of all atoms must be zero.
For oxygen, the oxidation number is usually \( -2 \), and for chlorine, it can vary.
Step 2: Assign oxidation numbers
In \( \text{Cl}_2 \text{O} \), there are two chlorine atoms and one oxygen atom.
- Let the oxidation number of chlorine be \( x \).
- The oxidation number of oxygen is \( -2 \).
The sum of oxidation numbers in \( \text{Cl}_2 \text{O} \) must be zero: \[ 2x + (-2) = 0 \] \[ 2x - 2 = 0 \] \[ 2x = 2 \] \[ x = +1 \]
Answer:
Therefore, the oxidation number of chlorine in \( \text{Cl}_2 \text{O} \) is \( +1 \). So, the correct answer is option (1).
Given below are two statements:
Statement (I): The first ionization energy of Pb is greater than that of Sn.
Statement (II): The first ionization energy of Ge is greater than that of Si.
In light of the above statements, choose the correct answer from the options given below:
The product (A) formed in the following reaction sequence is:
