Step 1: Understanding the Circuit
The given circuit consists of: - A NOR gate producing \( (A + \overline{B}) \), - An AND gate taking \( (A + \overline{B}) \) and \( \overline{A} \cdot B \) as inputs, - A final truth table evaluation.
Step 2: Determining the Boolean Expression
The circuit expression is given as: \[ Y = (A + \overline{B}) \cdot (\overline{A} \cdot B) \]
Step 3: Constructing the Truth Table
From the table, we observe that for all inputs, the output remains \( 0 \).
Step 4: Conclusion
Since the output of the circuit is always \( 0 \), the correct answer is \( Y = 0 \).
Final Answer: The output \( Y \) is always \( 0 \).
For a given reaction \( R \rightarrow P \), \( t_{1/2} \) is related to \([A_0]\) as given in the table. Given: \( \log 2 = 0.30 \). Which of the following is true?
\([A]\) (mol/L) | \(t_{1/2}\) (min) |
---|---|
0.100 | 200 |
0.025 | 100 |
A. The order of the reaction is \( \frac{1}{2} \).
B. If \( [A_0] \) is 1 M, then \( t_{1/2} \) is \( 200/\sqrt{10} \) min.
C. The order of the reaction changes to 1 if the concentration of reactant changes from 0.100 M to 0.500 M.
D. \( t_{1/2} \) is 800 min for \( [A_0] = 1.6 \) M.