Step 1: Understanding the Circuit
The given circuit consists of: - A NOR gate producing \( (A + \overline{B}) \), - An AND gate taking \( (A + \overline{B}) \) and \( \overline{A} \cdot B \) as inputs, - A final truth table evaluation.
Step 2: Determining the Boolean Expression
The circuit expression is given as: \[ Y = (A + \overline{B}) \cdot (\overline{A} \cdot B) \]
Step 3: Constructing the Truth Table
From the table, we observe that for all inputs, the output remains \( 0 \).
Step 4: Conclusion
Since the output of the circuit is always \( 0 \), the correct answer is \( Y = 0 \).
Final Answer: The output \( Y \) is always \( 0 \).
Consider the following statements:
(A) Availability is generally conserved.
(B) Availability can neither be negative nor positive.
(C) Availability is the maximum theoretical work obtainable.
(D) Availability can be destroyed in irreversibility's.
List-I (Details of the processes of the cycle) | List-II (Name of the cycle) |
---|---|
(A) Two adiabatic, one isobaric and two isochoric | (I) Diesel |
(B) Two adiabatic and two isochoric | (II) Carnot |
(C) Two adiabatic, one isobaric and one isochoric | (III) Dual |
(D) Two adiabatics and two isothermals | (IV) Otto |