Penetration power refers to how close an electron in a given orbital can get to the nucleus. The penetration power of orbitals follows the order: s > p > d > f This means electrons in s-orbitals are found closer to the nucleus on average, and thus have the highest penetration. This higher penetration leads to stronger attraction to the nucleus and lower energy compared to other orbitals in the same shell.
The correct answer is option (A): \(s\)
The correct orders among the following are:
[A.] Atomic radius : \(B<Al<Ga<In<Tl\)
[B.] Electronegativity : \(Al<Ga<In<Tl<B\)
[C.] Density : \(Tl<In<Ga<Al<B\)
[D.] 1st Ionisation Energy :
In\(<Al<Ga<Tl<B\)
Choose the correct answer from the options given below :
Given below are two statements:
Statement I: $ H_2Se $ is more acidic than $ H_2Te $
Statement II: $ H_2Se $ has higher bond enthalpy for dissociation than $ H_2Te $
In the light of the above statements, choose the correct answer from the options given below.