Question:

The orbital angular momentum of an electron in 2S orbital is

Updated On: Mar 18, 2024
  • \(+\frac{1}{2}\frac{h}{2\pi}\)
  • zero
  • \(-\frac{1}{2}\frac{h}{2\pi}\)
  • \(\frac{h}{2\pi}\)
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The Correct Option is B

Solution and Explanation

The correct answer is B() : zero
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