Question:
The orbital angular momentum of a p-electron is given as
The orbital angular momentum of a p-electron is given as
Updated On: Jun 7, 2022
- $\frac{h}{\sqrt{2}\pi}$
- $\sqrt{3} \frac{h}{2 \pi}$
- $\sqrt{\frac{3}{2}} \frac{h}{\pi}$
- $\sqrt{6} \frac{h}{2 \pi}$
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The Correct Option is A
Solution and Explanation
Orbital angular momentum $(m)$
$ = \sqrt{l(l+1)} \frac{h}{2 \pi}$
For $p$-electron; $l = 1$
Thus, $m = \sqrt{1\left(1+1\right)} \frac{h}{2\pi}= \frac{\sqrt{2}h}{2\pi} = \frac{h}{\sqrt{2}\pi}$
$ = \sqrt{l(l+1)} \frac{h}{2 \pi}$
For $p$-electron; $l = 1$
Thus, $m = \sqrt{1\left(1+1\right)} \frac{h}{2\pi}= \frac{\sqrt{2}h}{2\pi} = \frac{h}{\sqrt{2}\pi}$
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Concepts Used:
Momentum
It can be defined as "mass in motion." All objects have mass; so if an object is moving, then it is called as momentum.
the momentum of an object is the product of mass of the object and the velocity of the object.
Momentum = mass • velocity
The above equation can be rewritten as
p = m • v
where m is the mass and v is the velocity.
Momentum is a vector quantity and the direction of the of the vector is the same as the direction that an object.