Question:

The one which is least basic is

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More resonance delocalisation of nitrogen lone pair decreases basicity. Triphenylamine has maximum delocalisation, hence least basic.
Updated On: Jan 3, 2026
  • \(NH_3\)
  • \(C_6H_5NH_2\)
  • \((C_6H_5)_3N\)
  • \((C_6H_5)_2NH\)
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The Correct Option is C

Solution and Explanation

Step 1: Basicity depends on availability of lone pair.
More available lone pair \(\Rightarrow\) stronger base.
Step 2: Compare aromatic amines.
In aniline and its derivatives, lone pair on nitrogen delocalizes into benzene ring by resonance, reducing basicity.
Step 3: Triphenylamine case.
In \((C_6H_5)_3N\), lone pair is delocalized into three phenyl rings.
So resonance withdrawal is maximum and lone pair becomes least available for protonation.
Hence it is least basic.
Final Answer: \[ \boxed{(C_6H_5)_3N} \]
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