Step 1: Count without restriction.
Choose ladies: \(\binom{8}{3}=56\). Choose gentlemen: \(\binom{7}{4}=35\).
Total committees (no restriction) \(= 56 \times 35 = 1960\).
Step 2: Subtract forbidden committees (both Mrs. X and Mr. Y included).
If both are included, then:
\(\bullet\) Ladies: Mrs. X is fixed; choose remaining \(2\) from the other \(7\) ladies \(\Rightarrow \binom{7}{2}=21\).
\(\bullet\) Gentlemen: Mr. Y is fixed; choose remaining \(3\) from the other \(6\) gentlemen \(\Rightarrow \binom{6}{3}=20\).
Forbidden count \(= 21 \times 20 = 420\).
Step 3: Apply restriction.
Valid committees \(= 1960 - 420 = \boxed{1540}\).
The number of strictly increasing functions \(f\) from the set \(\{1, 2, 3, 4, 5, 6\}\) to the set \(\{1, 2, 3, ...., 9\}\) such that \(f(i)>i\) for \(1 \le i \le 6\), is equal to: