Question:

The number of ways in which a committee of 3 ladies and 4 gentlemen can be appointed out of 8 ladies and 7 gentlemen, if Mrs. X refuses to serve in a committee of which Mr. Y is a member, is

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For "A will not serve with B" constraints, use "Total \(-\) Together" counting: compute all possibilities, then subtract the cases where the incompatible pair appears together.
Updated On: Dec 11, 2025
  • 1,540
  • 1,960
  • 3,240
  • None of these
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The Correct Option is A

Solution and Explanation

Step 1: Count without restriction. 
Choose ladies: \(\binom{8}{3}=56\). Choose gentlemen: \(\binom{7}{4}=35\). 
Total committees (no restriction) \(= 56 \times 35 = 1960\). 

Step 2: Subtract forbidden committees (both Mrs. X and Mr. Y included). 
If both are included, then: 
\(\bullet\) Ladies: Mrs. X is fixed; choose remaining \(2\) from the other \(7\) ladies \(\Rightarrow \binom{7}{2}=21\). 
\(\bullet\) Gentlemen: Mr. Y is fixed; choose remaining \(3\) from the other \(6\) gentlemen \(\Rightarrow \binom{6}{3}=20\). 
Forbidden count \(= 21 \times 20 = 420\). 

Step 3: Apply restriction. 
Valid committees \(= 1960 - 420 = \boxed{1540}\).

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