Question:
The number of wait states required to interface 8279 to 8086 with an 8MHz clock are:
The number of wait states required to interface 8279 to 8086 with an 8MHz clock are:
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Wait states are used to synchronize data transfer between faster and slower devices in a system.
Updated On: Dec 29, 2024
- 2
- 3
- 1
- 5
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The Correct Option is B
Solution and Explanation
The 8279 programmable keyboard/display interface requires a slower clock cycle compared to the 8086 microprocessor operating at 8 MHz. To synchronize the data transfer between the two devices, wait states are introduced. For an 8 MHz clock, the calculation for the number of wait states shows that 3 wait states are needed for proper interfacing.
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