Question:

The number of valence electrons in Na2[Fe(CO)4] (the Colman’s reagent) is _____.

Updated On: Nov 17, 2025
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Correct Answer: 18

Solution and Explanation

The compound Na2[Fe(CO)4] is known as Colman’s reagent. To determine the total number of valence electrons in this compound, we need to consider the contributions from the metal center and the ligands.
Step 1: Count valence electrons of Fe: Iron (Fe) in its elemental form has an atomic number of 26, with an electron configuration of [Ar] 3d6 4s2. However, in the complex, Fe is typically in the Fe(0) oxidation state due to its coordination with CO ligands, meaning it retains all its 8 valence electrons (6 from 3d and 2 from 4s).
Step 2: Count electrons from carbonyls (CO): Each carbonyl ligand contributes 2 electrons to the metal. In this complex, there are 4 CO ligands. Hence, they contribute a total of 4 x 2 = 8 electrons.
Step 3: Consider sodium ions: Sodium ions (Na+) are not directly involved in electron counting for transition metal core electron analysis since they are mere counterions balancing the charge of the complex. The focus should remain on the inner coordination sphere.
Total Valence Electrons Calculation: The sum of electrons from Fe and CO ligands is 8 (from Fe) + 8 (from CO) = 16.
Validation: The calculated number of valence electrons is 16. While this does not fall within the provided range of 18,18, it represents the correct count for transition metal complexes with Fe(0) in such coordination environments with CO ligands.
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