Question:

The number of unpaired electrons in $\left[NiCl_{4}\right]^{2-}, Ni\left(CO\right)_{4}$ and $\left[Cu\left(NH_{3}\right)_{4}\right]^{2+}$ respectively are :

Updated On: Jun 18, 2022
  • $2, 2, 1$
  • $2, 0, 1$
  • $0, 2, 1$
  • $2, 2, 0$
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The Correct Option is B

Solution and Explanation

Configuration for metal $(M)$ in various complex.



$Ni ^{2+}$ has $2$ unpaired electrons



$Ni ^{0}$ has zero unpaired electrons with $s p^{3}$-hybridisation.



$Cu ^{2+}$ has one unpaired electron with $d s p^{2}$-hybridisation.
$\therefore (b) $ is the correct answer, i.e.
Number of unpaired electron $(2,0,1)$
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Concepts Used:

Coordination Compounds

A coordination compound holds a central metal atom or ion surrounded by various oppositely charged ions or neutral molecules. These molecules or ions are re-bonded to the metal atom or ion by a coordinate bond.

Coordination entity:

A coordination entity composes of a central metal atom or ion bonded to a fixed number of ions or molecules.

Ligands:

A molecule, ion, or group which is bonded to the metal atom or ion in a complex or coordination compound by a coordinate bond is commonly called a ligand. It may be either neutral, positively, or negatively charged.