Question:

The number of sp3 hybridised carbons in an acyclic neutral compound with molecular formula C4H5N is ________.

Updated On: Sep 24, 2024
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Correct Answer: 1

Solution and Explanation

C4H5N
DBE=(C+1)-(\(\frac{H+X-N}{2}\))
=(4+1)-(\(\frac{5-1}{2}\))=5-2=3
Three double-bond equivalents are present in the compound
double-bond equivalents are present in the compound
Only 1 sp3 hybridised carbon is there
(Keeping compound as acyclic)

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