Step 1: Understanding the Concept:
The "never together" condition is usually handled by subtracting the cases where they all come together from the total permutations.
Step 2: Detailed Explanation:
The word 'VOWELS' has 6 letters: V, W, L, S (4 consonants) and O, E (2 vowels).
1. Total number of words:
Since all letters are distinct, Total = \(6! = 720\).
2. Cases where all consonants are together:
Treat {V, W, L, S} as one block. We then have 3 entities: {VWLS}, O, E.
Permutations of these 3 entities = \(3!\).
Internal permutations of the 4 consonants = \(4!\).
Together = \(3! \times 4! = 6 \times 24 = 144\).
3. Cases where all consonants never come together:
Result = Total - Together = \(720 - 144 = 576\).
Step 3: Final Answer:
The number of such words is 576.