Question

The number of recombinants in the 1280 progeny obtained through a dihybrid cross of Mendel in the F₂ generation.

• A. 240
• B. 360
• C. 720
• D. 480

Hint:

In a dihybrid cross, recombinants appear with a probability of \( \frac{6}{16} \) (or \( \frac{3}{8} \)) of the total progeny.

Answer 1

The Correct Option is D

Step 1: Understanding Recombinants in a Dihybrid Cross In a Mendelian dihybrid cross, the recombinant frequency follows a \(9:3:3:1\) phenotypic ratio. Recombinants are those that do not resemble the parental types. 
Step 2: Calculating the Expected Recombinants The fraction of recombinants is given by: \[ \frac{3+3}{16} = \frac{6}{16} = \frac{3}{8} \] Multiplying by the total progeny: \[ \frac{3}{8} \times 1280 = 480. \]