Question

The number of protons, neutrons and electrons in the ion \(^{32}_{16}S^{2-}\) respectively are

• A. 16, 18, 16
• B. 16, 16, 18
• C. 18, 16, 16
• D. 16, 16, 16

Answer 1

The Correct Option is B

The ion in question is 16 32S²⁻, which is the sulfide ion with a 2-negative charge. Let's determine the number of protons, neutrons, and electrons in this ion:

Explanation: 

Protons: The atomic number of sulfur (S) is 16, which means it has 16 protons in its nucleus. The number of protons does not change with the charge of the ion, so the number of protons is 16.

Neutrons: The mass number of sulfur is 32 (as shown in the notation 16 32S), which is the sum of protons and neutrons. Therefore, the number of neutrons is: \[ \text{Neutrons} = \text{Mass number} - \text{Protons} = 32 - 16 = 16 \] So, the number of neutrons is 16.

Electrons: The sulfide ion (S²⁻) has gained 2 electrons, which means the number of electrons is the number of protons plus 2. Since there are 16 protons, the number of electrons is: \[ \text{Electrons} = \text{Protons} + 2 = 16 + 2 = 18 \] So, the number of electrons is 18.

Conclusion:

The number of protons, neutrons, and electrons in the ion 16 32S²⁻ are:

• Protons: 16
• Neutrons: 16
• Electrons: 18

 

Answer: Option D: 16, 16, 18