The chemical reaction for the formation of KMnO4 will look like–
2KMnO4 + KI + H2O → KIO3 + 2MnO2 + 2KOH
While determining the oxidation number from this reaction following values will be obtained-
Iodine's oxidation number increases from -1 in KI to +5 in KIO3
But Magnesium’s oxidation number decreases from +7 in KMnO4 to +4 in MnO2
Oxidation number decrease in Mn will be 3 and for 2 such Mn atoms it’ll sum up to 6.
During the reduction reaction, the charge of 1 Iodine atom is balanced by 2 Mn atoms so, the correct answer will be 2 Moles of KMnO4 is reduced during the reaction.
A few mentionable characteristics of KMnO4 are–
List-I Alkali Metal | List-II Emission Wavelength in nm |
---|---|
(A) Li | (I) 589.2 |
(B) Na | (II) 455.5 |
(C) Rb | (III) 670.8 |
(D) Cs | (IV) 780.0 |
The d-block elements are placed in groups 3-12 and F-block elements with 4f and 5f orbital filled progressively. The general electronic configuration of d block elements and f- block elements are (n-1) d 1-10 ns 1-2 and (n-2) f 1-14 (n-1) d1 ns2 respectively. They are commonly known as transition elements because they exhibit multiple oxidation states because of the d-d transition which is possible by the availability of vacant d orbitals in these elements.
They have variable Oxidation States as well as are good catalysts because they provide a large surface area for the absorption of reaction. They show variable oxidation states to form intermediate with reactants easily. They are mostly lanthanoids and show lanthanoid contraction. Since differentiating electrons enter in an anti-penultimate f subshell. Therefore, these elements are also called inner transition elements.
Read More: The d and f block elements