The number of angular nodes and radial nodes in an orbital can be determined by the following formulas:
1. Angular nodes: The number of angular nodes is equal to \( l \), where \( l \) is the azimuthal quantum number. For a 'd' orbital, \( l = 2 \).
Therefore, the number of angular nodes is:
\[ \text{Angular nodes} = l = 2 \] 2. Radial nodes: The number of radial nodes is given by the formula:
\[ \text{Radial nodes} = n - l - 1 \] where \( n \) is the principal quantum number. For the '4d' orbital, \( n = 4 \) and \( l = 2 \). So, the number of radial nodes is:
\[ \text{Radial nodes} = 4 - 2 - 1 = 1 \]
Thus, the number of angular nodes is 2, and the number of radial nodes is 1.
Therefore, the correct answer is:
\[ \boxed{\text{A) 2, 1}} \]
In the Carius method of estimation of halogen, 0.4g of an organic compound gave 0.188g of AgBr. What is the percentage of bromine in the organic compound? (The atomic mass of Ag = 108 g mol\(^{-1}\) & Br = 80 g mol\(^{-1}\))
For the reaction:
\[ 2A + B \rightarrow 2C + D \]
The following kinetic data were obtained for three different experiments performed at the same temperature:
\[ \begin{array}{|c|c|c|c|} \hline \text{Experiment} & [A]_0 \, (\text{M}) & [B]_0 \, (\text{M}) & \text{Initial rate} \, (\text{M/s}) \\ \hline I & 0.10 & 0.10 & 0.10 \\ II & 0.20 & 0.10 & 0.40 \\ III & 0.20 & 0.20 & 0.40 \\ \hline \end{array} \]
The total order and order in [B] for the reaction are respectively: