1. Recall the formulas for calculating the number of nodes:
Number of radial nodes = n - l - 1
Number of angular nodes = l
Total number of nodes = n - 1
where:
n is the principal quantum number
l is the azimuthal quantum number
2. Determine the quantum numbers for a 3p orbital:
For a 3p orbital:
n = 3
l = 1 (since p orbital corresponds to l = 1)
3. Calculate the number of radial and angular nodes:
Number of angular nodes = l = 1
Number of radial nodes = n - l - 1 = 3 - 1 - 1 = 1
The number of angular and radial nodes in a 3p orbital are 1 and 1 respectively.
Final Answer:
(B) 1, 1
The number of angular nodes (l) is equal to the value of the azimuthal quantum number (l), and the number of radial nodes is given by the formula:
Number of radial nodes = n - l - 1
For a 3p orbital, n = 3 (principal quantum number) and l = 1 (for p orbitals).
Thus, the number of angular nodes is:
Angular nodes = l = 1
The number of radial nodes is:
Radial nodes = n - l - 1 = 3 - 1 - 1 = 1
The correct answer is (B) : 1, 1.
Among the following, identify the compound that is not an isomer of hexane:
In an experiment to determine the figure of merit of a galvanometer by half deflection method, a student constructed the following circuit. He applied a resistance of \( 520 \, \Omega \) in \( R \). When \( K_1 \) is closed and \( K_2 \) is open, the deflection observed in the galvanometer is 20 div. When \( K_1 \) is also closed and a resistance of \( 90 \, \Omega \) is removed in \( S \), the deflection becomes 13 div. The resistance of galvanometer is nearly:
A block of certain mass is placed on a rough floor. The coefficients of static and kinetic friction between the block and the floor are 0.4 and 0.25 respectively. A constant horizontal force \( F = 20 \, \text{N} \) acts on it so that the velocity of the block varies with time according to the following graph. The mass of the block is nearly (Take \( g = 10 \, \text{m/s}^2 \)):