We are asked to find the number of 3-digit numbers that can be formed from the digits 0, 2, 3, 5, and 7, where repetition is allowed.
For a 3-digit number, the first digit cannot be 0, so it must be one of the digits 2, 3, 5, or 7. Therefore, there are 4 possible choices for the first digit.
The second and third digits can be any of the 5 given digits (0, 2, 3, 5, or 7), so there are 5 choices for each of these digits.
Thus, the total number of 3-digit numbers is:
\(4 \times 5 \times 5 = 100\)
The number of 3-digit numbers that can be formed is 100.
Match List-I with List-II
List-I | List-II |
---|---|
(A) \(^{8}P_{3} - ^{10}C_{3}\) | (I) 6 |
(B) \(^{8}P_{5}\) | (II) 21 |
(C) \(^{n}P_{4} = 360,\) then find \(n\). | (III) 216 |
(D) \(^{n}C_{2} = 210,\) find \(n\). | (IV) 6720 |
Choose the correct answer from the options given below: