We are asked to find the number of 3-digit numbers that can be formed from the digits 0, 2, 3, 5, and 7, where repetition is allowed.
For a 3-digit number, the first digit cannot be 0, so it must be one of the digits 2, 3, 5, or 7. Therefore, there are 4 possible choices for the first digit.
The second and third digits can be any of the 5 given digits (0, 2, 3, 5, or 7), so there are 5 choices for each of these digits.
Thus, the total number of 3-digit numbers is:
\(4 \times 5 \times 5 = 100\)
The number of 3-digit numbers that can be formed is 100.
The number of strictly increasing functions \(f\) from the set \(\{1, 2, 3, 4, 5, 6\}\) to the set \(\{1, 2, 3, ...., 9\}\) such that \(f(i)>i\) for \(1 \le i \le 6\), is equal to: