Step 1: In IEEE single-precision format, the first bit represents the sign (1 for negative, 0 for positive), the next 8 bits are the exponent, and the remaining 23 bits are the mantissa.
Step 2: The given representation is: \[ 1 { } 10000000 { } 010...000 \] Sign bit is 1, thus it is a negative number. Exponent bits are \( 10000000 = 128\). The bias for single precision is 127, so exponent \( E = 128 - 127 = 1 \). Mantissa is \(1.01\), where we need to add 1 before the mantissa.
Step 3: The decimal value is \[ (-1)^1 \times (1.25) \times 2^1 = -1 \times 1.25 \times 2 = -2.5 \]
Let \( G(s) = \frac{1}{(s+1)(s+2)} \). Then the closed-loop system shown in the figure below is:
The open-loop transfer function of the system shown in the figure is: \[ G(s) = \frac{K s (s + 2)}{(s + 5)(s + 7)} \] For \( K \geq 0 \), which of the following real axis point(s) is/are on the root locus?
A closed-loop system has the characteristic equation given by: $ s^3 + k s^2 + (k+2) s + 3 = 0 $.
For the system to be stable, the value of $ k $ is: