The momentum of a photon of energy 1 MeV in kg m/s, will be :
- 0.33 x 106
- 8 x 10-24
- 5 x 10-23
- 5 x 10-22
The Correct Option is D
Solution and Explanation
The momentum of a photon can be calculated using the formula: p =\(\frac{E}{c}\), where E is the energy and c is the speed of light.
Given that the energy is 1 MeV (1 MeV = 1.6 x 10-13 Joules) and the speed of light is approximately 3 x 108 m/s, we can calculate p as follows:
p = \(\frac{(1.6 x 10^{-13} J)} {(3 x 10^8 m/s) }\)= 5.33 x 10-22 kg m/s.
Therefore, the correct option is (D): 5 x 10-22
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Concepts Used:
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The dual nature of matter and the dual nature of radiation were throughgoing concepts of physics. At the beginning of the 20th century, scientists untangled one of the best-kept secrets of nature – the wave-particle duplexity or the dual nature of matter and radiation.
Electronic Emission
The least energy that is needed to emit an electron from the surface of a metal can be supplied to the loose electrons.
Photoelectric Effect
The photoelectric effect is a phenomenon that involves electrons getting away from the surface of materials.
Heisenberg’s Uncertainty Principle
Heisenberg’s Uncertainty Principle states that both the momentum and position of a particle cannot be determined simultaneously.