The molarity of $NO_3^-$ in the solution after $2L$ of $3M \, AgNO_3$ is mixed with $3L$ of $1M \, BaCl_2$ is
- 1.2 M
- 1.8 M
- 0.5 M
- 0.4 M
The Correct Option is A
Solution and Explanation
\(2\,L\) of \(3M \, AgNO_3\) will contains \(6\) moles of \(AgNO_3\).
\(3\,L\) of \(1 \, M \, BaCl_2\) will contain \(3\) moles of \(BaCl_2\).
\({2AgNO_3 + BaCl_2 \to2AgCl + Ba(NO_3)_2. }\)
So, 6 moles of \(AgNO_3\) will react with 3 moles on \(BaCl_2\) it means, two solution will react completely to form 3 moles of \(Ba(NO_3)_2 \equiv\) 6 moles of \(NO_3^-\) ions in \(2+35L\) solution
Hence, molarity of \(NO_3^- = \frac{6}{5} = 1.2 \, M\)
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Concepts Used:
Concentration of Solutions
It is the amount of solute present in one liter of solution.
Concentration in Parts Per Million - The parts of a component per million parts (106) of the solution.
Mass Percentage - When the concentration is expressed as the percent of one component in the solution by mass it is called mass percentage (w/w).
Volume Percentage - Sometimes we express the concentration as a percent of one component in the solution by volume, it is then called as volume percentage
Mass by Volume Percentage - It is defined as the mass of a solute dissolved per 100mL of the solution.
Molarity - One of the most commonly used methods for expressing the concentrations is molarity. It is the number of moles of solute dissolved in one litre of a solution.
Molality - Molality represents the concentration regarding moles of solute and the mass of solvent.
Normality - It is the number of gram equivalents of solute present in one liter of the solution and it is denoted by N.
Formality - It is the number of gram formula present in one litre of solution.