Question:

The molality and molarity of a solution of glucose in water which is labeled as 10% (w/w) are respectively (density of solution = 1.2 g/mL)

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Use density to find volume when mass is known
Molality = moles per kg of solvent, Molarity = moles per liter of solution
Updated On: May 19, 2025
  • 0.57 m, 0.517 M
  • 0.67 m, 0.61 M
  • 0.611 m, 0.67 M
  • 0.517 m, 0.57 M
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The Correct Option is C

Solution and Explanation

Assume 100 g of solution: - Glucose = 10 g - Water = 90 g = 0.090 kg Molality: \[ \text{Mol. mass of glucose} = 180 \text{ g/mol},\quad \text{mol} = \frac{10}{180} = 0.0556 \] \[ m = \frac{0.0556}{0.090} \approx 0.617 \approx 0.611 \text{ mol/kg} \] Molarity: \[ \text{Volume} = \frac{100}{1.2} = 83.33 \text{ mL} = 0.08333 \text{ L} \] \[ M = \frac{0.0556}{0.08333} \approx 0.67 \text{ mol/L} \]
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