Question

The minimum of \(f(x)=\sqrt{(10-x^2)}\) in the interval \([-3,2]\) is

• A. \(\sqrt4\)
• B. \(\sqrt6\)
• C. \(1\)
• D. \(0\)
• E. \(\sqrt10\)

Answer 1

The Correct Option is C

Given that:
\(f(x) = √ (10 − x^2)\)  
So,
\(f(x) = \sqrt{(10 − x^2)}\)  is maximum when \(x^2\) is maximum.
Then, for [-3,2]
\(f(x) = √ (10 − x^2)\)  such that :
∴ minimum of \(f(x) = \sqrt{(10 − 9 )}\)
\(= \sqrt1 =1\)
So, the correct option is (C) : 1.