Question:

The minimum number of flip-flops required to design a mod-10 counter is:

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Use \( 2^n \geq \text{MOD} \) to determine flip-flop count for counters.
Updated On: June 02, 2025
  • 3
  • 4
  • 5
  • 10
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The Correct Option is B

Solution and Explanation

To count up to 10 states (0–9), we need: \[ 2^n \geq 10 \Rightarrow n = 4\ \text{flip-flops} \]
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