Question:
The mean of the following distribution is 25.
\[
\begin{array}{|c|c|}
\hline
\text{Class} & \text{Frequency} \\
\hline
0-10 & 14 \\
10-20 & p \\
20-30 & 27 \\
30-40 & 21 \\
40-50 & 15 \\
\hline
\end{array}
\]
The mean of the following distribution is 25.
\[
\begin{array}{|c|c|}
\hline
\text{Class} & \text{Frequency} \\
\hline
0-10 & 14 \\
10-20 & p \\
20-30 & 27 \\
30-40 & 21 \\
40-50 & 15 \\
\hline
\end{array}
\]
Show Hint
For frequency distributions, to calculate the mean, multiply each class midpoint by the corresponding frequency, then divide by the total number of observations.
Updated On: Apr 19, 2025
- 18
- 20
- 21
- 23
Hide Solution
Verified By Collegedunia
The Correct Option is B
Solution and Explanation
We use the formula for mean \( \bar{x} = \frac{\sum f_i x_i}{\sum f_i} \). Given that the mean is 25, we can calculate the value of \( p \) by solving for the equation.
Was this answer helpful?
0
0
Top Questions on Statistics
- If the mean and variance of observations \( x, y, 12, 14, 4, 10, 2 \) is \(8\) and \(16\) respectively, where \( x>y \), then the value of \( 3x - y \) is:
- JEE Main - 2026
- Mathematics
- Statistics
Consider the following frequency distribution:
Value 4 5 8 9 6 12 11 Frequency 5 $ f_1 $ $ f_2 $ 2 1 1 3 Suppose that the sum of the frequencies is 19 and the median of this frequency distribution is 6.
For the given frequency distribution, let:
- $ \alpha $ denote the mean deviation about the mean
- $ \beta $ denote the mean deviation about the median
- $ \sigma^2 $ denote the variance
Match each entry in List-I to the correct entry in List-II and choose the correct option.
List-I
- (P) $ 7f_1 + 9f_2 $ is equal to
- (Q) $ 19\alpha $ is equal to
- (R) $ 19\beta $ is equal to
- (S) $ 19\sigma^2 $ is equal to
List-II
- (1) 146
- (2) 47
- (3) 48
- (4) 145
- (5) 55
- Marks obtained by all the students of class 12 are presented in a frequency distribution with classes of equal width. Let the median of this grouped data be 14 with median class interval 12-18 and median class frequency 12. If the number of students whose marks are less than 12 is 18, then the total number of students is:
- JEE Main - 2025
- Mathematics
- Statistics
- If a 95% confidence interval for a population mean was reported to be 132 to 160 and sample standard deviation s = 50, then the size of the sample in the study is:
(Given \(Z_{0.025}\) = 1.96)- CUET (UG) - 2025
- Mathematics
- Statistics
- Which of the following are the assumptions underlying the use of t-distribution?
(A) The variance of population is known.
(B) The samples are drawn from a normally distributed population.
(C) Sample standard deviation is an unbiased estimate of the population variance.
(D) It depends on a parameter known as degree of freedom.
Choose the correct answer from the options given below:- CUET (UG) - 2025
- Mathematics
- Statistics
View More Questions
Questions Asked in NPAT exam
- Based on the given image, which of the following options must be true?
- NPAT - 2025
- Visual Reasoning
- A can draw 10 illustrations in 5 days. B is three times as productive in twice the amount of time (in comparison to A). How many illustrations can B draw in a day?
- NPAT - 2025
- Time and Work
- A, B and C have some marbles. The ratio of the number of marbles with A to the number with B is 2:1. Also, the number of marbles with A to the number with C is 1:4. What is the approximate percentage of the total number of marbles that are with C?
- NPAT - 2025
- Percentages
- If \( p \) and \( q \) are numbers such that the pair of linear equations \( (p + 2)x + (q - 1)y = 10 \) and \( (q + 2)x + (p - 1)y = 10 \) have infinite solutions for \( x \) and \( y \), then \( p = q \).
- NPAT - 2025
- Linear Equations
- If \( x \), \( y \), and \( z \) are positive integers and \( p = \left( \left( (x - 1)^2 / |x| \right) + 2 \right) + \left( \left( (y - 1)^2 / |y| \right) + 2 \right) + \left( \left( (z - 1)^2 / |z| \right) + 2 \right), \) then \( p<6 \).
- NPAT - 2025
- Algebra
View More Questions