Question:
The mean free path of collision of gas molecules varies with its diameter $(d)$ of the molecules as
The mean free path of collision of gas molecules varies with its diameter $(d)$ of the molecules as
Updated On: Jun 18, 2022
- $d^{-1}$
- $d^{-2}$
- $d^{-3}$
- $d^{-4}$
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The Correct Option is B
Solution and Explanation
Mean free path of gas molecules
$\lambda=\frac{\lambda_{1}+\lambda_{2}+\ldots+\lambda_{n}}{n}$
$\lambda =\frac{1}{\sqrt{2} \pi n d^{2}}$
$\lambda \propto d^{-2}$
$\lambda=\frac{\lambda_{1}+\lambda_{2}+\ldots+\lambda_{n}}{n}$
$\lambda =\frac{1}{\sqrt{2} \pi n d^{2}}$
$\lambda \propto d^{-2}$
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