Question:

The maximum value of Z = 3x + 4y subject to constraint x + y ≤6, x, y ≥ 0 is:

Updated On: May 11, 2025
  • 18
  • 20
  • 22
  • 24
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The Correct Option is D

Solution and Explanation

To find the maximum value of \( Z = 3x + 4y \) subject to the constraint \( x + y \leq 6 \) and \( x, y \geq 0 \), we need to determine the feasible region and evaluate the objective function at the vertices of this region. The constraint can be rewritten as \( y \leq 6 - x \).

1. Graphical Representation:

Let's plot the line \( y = 6 - x \) and consider the constraints:

  • \( x \geq 0 \)
  • \( y \geq 0 \)
  • \( x + y \leq 6 \)

The feasible region is a triangle with vertices at \( (0,0) \), \( (6,0) \), and \( (0,6) \).

2. Evaluate the Objective Function at Each Vertex:

\(Z = 3x + 4y\)Vertex \( (x,y) \)Value of \( Z \)
\((0,0)\)\(Z = 3(0) + 4(0) = 0\) 
\((6,0)\)\(Z = 3(6) + 4(0) = 18\) 
\((0,6)\)\(Z = 3(0) + 4(6) = 24\) 

3. Determine the Maximum Value:

The maximum value of \( Z \) is \( 24 \) at the vertex \( (0,6) \).

Therefore, the maximum value of \( Z = 3x + 4y \) under the given constraints is \( \mathbf{24} \).

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