Question:

The maximum value of Z= 2x + 3y subject to the constraints x≥0, y>0; x+y≤ 10, 3x+4y≤ 36 is:

Updated On: May 11, 2025
  • 20
  • 27
  • 30
  • 0
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The Correct Option is B

Solution and Explanation

To determine the maximum value of Z=2x+3y given the constraints x≥0, y>0; x+y≤10, and 3x+4y≤36, we will use the graphical method for solving linear programming problems.
StepDescription
1Identify the feasible region by graphing the constraints on the xy-plane.
2Graph x+y=10. This is a line passing through the points (0,10) and (10,0).
3Graph 3x+4y=36. This line passes through (0,9) and (12,0).
4Identify the feasible region where all constraints overlap, considering x≥0 and y>0.
5Determine the vertices of the feasible region. They are (0,0), (0,9), (4,6), and (10,0).
6Calculate Z=2x+3y for each vertex:
  • (0,0): Z=2(0)+3(0)=0
  • (0,9): Z=2(0)+3(9)=27
  • (4,6): Z=2(4)+3(6)=8+18=26
  • (10,0): Z=2(10)+3(0)=20
7Identify the maximum value: Z=27 at (0,9).
The maximum value of Z is 27, confirming the correct answer is 27.
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