Question:

The maximum elongation of a steel wire of 1 m length if the elastic limit of steel and its Young’s modulus, respectively, are 8 × 108 N m–2 and 2 × 1011 N m–2, is :

Updated On: Dec 4, 2024
  • 4 mm
  • 0.4 mm
  • 40 mm
  • 8 mm
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The Correct Option is A

Solution and Explanation

Maximum elongation is calculated using\(  \Delta L = \frac{\sigma L}{Y}\).  Substituting values:
\(\Delta L = \frac{8 \times 10^8 \times 1}{2 \times 10^{11}} = 4 \, mm\).

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