Question:
The maximum efficiency in a Screw Jack is given as:
The maximum efficiency in a Screw Jack is given as:
Updated On: Mar 21, 2024
- \(\frac{1+ cos\vartheta_s}{1-cos \vartheta_s}\)
- \(\frac{1-cos\vartheta_s}{1+cos \vartheta_s}\)
- \(\frac{1+sin \vartheta_s}{1-sin \vartheta_s}\)
- \(\frac{1-sin \vartheta_s}{1+sin \vartheta_s}\)
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
The correct option is (D): \(\frac{1-sin \vartheta_s}{1+sin \vartheta_s}\)
Was this answer helpful?
0
0
Top Questions on Efficiency of Screws
Questions Asked in CUET PG exam
- Which one will replace the question mark?
- CUET (PG) - 2025
- Logical Reasoning
- The period of a satellite in a circular orbit of radius 12000 km around a planet is 3 hours. Obtain the period of a satellite in a circular orbit of radius 48000 km around the same planet.
- CUET (PG) - 2025
- Gravitation
- Two satellites A and B go around a planet in circular orbits having radii of 4R and R, respectively. If the velocity of satellite A is 3v, the velocity of satellite B will be:
- CUET (PG) - 2025
- Gravitation
- Two satellites A and B of mass 'M' are orbiting the earth in circular orbits at altitudes 2R and 5R respectively, where R is the radius of the earth. The ratio of kinetic energies of satellite A and B will be
- CUET (PG) - 2025
- Gravitation
- Displacement of a particle at any instant of time t is y = 5 sin(100\(\pi\)t + \(\phi\)). The frequency of oscillation of the particle is:
View More Questions