Question:

The mass of the earth is $6 \times 10^{24}\, kg$ and that of the moon is $7.4 \times 10^{22}\, kg$. The potential energy of the system is $-7.79 \times 10^{28}\, J$. The mean distance between the earth and moon is $(G = 6.67 \times 10^{-11}\, N\, m^2kg^{-2})$

Updated On: Aug 15, 2022
  • $3.8 \times 10^8\, m$
  • $3.37 \times 10^6\, m$
  • $7.60 \times 10^4\, m$
  • $1.9 \times 10^2\, m$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Here, Potential energy of system, $U = - 7.79 \times 10^{28}\, J$ Mass of the earth, $M_E = 6 \times 10^{24}\, kg$ Mass of the moon, $M_M = 7.4 \times 10^{22}\, kg$ The potential energy of the earth-moon system is $U = -\frac{GM_{E}M_{M}}{r}$ where $r$ is the mean distance between earth and moon. $\therefore r = -\frac{GM_{E}M_{M}}{U}$ $= -\frac{6.67 \times10^{-11}\times 6\times 10^{24}\times 7.4\times 10^{22}}{-7.79 \times 10^{28}}$ $= 3.8\times 10^{8}\,m$
Was this answer helpful?
0
0

Top Questions on Gravitation

View More Questions

Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].