Question:
The mass of proton is 1.0073 u and that of neutron is 1.0087 u (u = atomic mass unit). The binding energy of \(_2^4 He\) is (Given: helium nucleus mass ≈ 4.0015 u)
The mass of proton is 1.0073 u and that of neutron is 1.0087 u (u = atomic mass unit). The binding energy of \(_2^4 He\) is (Given: helium nucleus mass ≈ 4.0015 u)
Updated On: Apr 21, 2025
- 0.0305 J
- 0.0305 erg
- 28.4 MeV
- 0.061 u
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The Correct Option is C
Solution and Explanation
Binding Energy of \(_2^4 He\):
BE = ∆m × 931
BE = [2(1.0087 + 1.0073) – 4.0015] × 931
BE = [4.032 - 4.0015] × 931
BE = 0.0305 × 931
BE = 28.4 MeV
So, the correct option is (C): 28.4 MeV
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Concepts Used:
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In the year 1911, Rutherford discovered the atomic nucleus along with his associates. It is already known that every atom is manufactured of positive charge and mass in the form of a nucleus that is concentrated at the center of the atom. More than 99.9% of the mass of an atom is located in the nucleus. Additionally, the size of the atom is of the order of 10-10 m and that of the nucleus is of the order of 10-15 m.
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