Step 1: Write electronic configuration of Zn\(^{2+}\).
Zn (Z=30) has configuration:
\[
Zn: [Ar]\,3d^{10}4s^2
\]
Zn\(^{2+}\) loses two 4s electrons:
\[
Zn^{2+}: [Ar]\,3d^{10}
\]
Step 2: Check unpaired electrons.
\(3d^{10}\) means all d-orbitals are completely filled.
So there are no unpaired electrons.
Step 3: Magnetic moment.
Magnetic moment depends on unpaired electrons:
\[
\mu = \sqrt{n(n+2)}
\]
Here \(n=0\), so:
\[
\mu = 0
\]
Final Answer:
\[
\boxed{0}
\]