Question:
The magnetic force exerted on a 3 m length conductor carrying 2A current when placed in a uniform magnetic field 0.4 T at an angle 30° is
The magnetic force exerted on a 3 m length conductor carrying 2A current when placed in a uniform magnetic field 0.4 T at an angle 30° is
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Use the formula \( F = BIL \sin(\theta) \) to calculate the force on a current-carrying conductor in a magnetic field.
Updated On: May 13, 2025
- 12 N
- 1.2 N
- 2.4 N
- 24 N
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The Correct Option is C
Solution and Explanation
The magnetic force on a current-carrying conductor is given by the formula \( F = B \cdot I \cdot L \cdot \sin(\theta) \), where \( B = 0.4 \, \text{T} \), \( I = 2 \, \text{A} \), \( L = 3 \, \text{m} \), and \( \theta = 30^\circ \).
\[
F = 0.4 \cdot 2 \cdot 3 \cdot \sin(30^\circ) = 2.4 \, \text{N}.
\]
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