Step 1: Understanding the Geometric Condition
Let the two fixed points be \( A(x_1, y_1) \) and \( B(x_2, y_2) \), and let the variable point be \( P(x, y) \). The area of the triangle formed by these three points is given by the determinant formula:
\[
\text{Area} = \frac{1}{2} \left| x_1(y_2 - y) + x_2(y - y_1) + x(y_1 - y_2) \right|.
\]
For a fixed area \( k \), we set:
\[
\frac{1}{2} \left| x_1(y_2 - y) + x_2(y - y_1) + x(y_1 - y_2) \right| = k.
\]
Step 2: Equation of the Locus
Rearranging,
\[
\left| x_1(y_2 - y) + x_2(y - y_1) + x(y_1 - y_2) \right| = 2k.
\]
This represents two straight-line equations, given by:
\[
x_1(y_2 - y) + x_2(y - y_1) + x(y_1 - y_2) = \pm 2k.
\]
Since these are linear equations in \( x \) and \( y \), the locus is a pair of parallel lines.
Step 3: Conclusion
Thus, the correct answer is that the locus of the variable point is a pair of parallel lines.